-5(3y-4)-y=4(y-5)

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Solution for -5(3y-4)-y=4(y-5) equation: 



-5(3y-4)-y=4(y-5)

We move all terms to the left:

-5(3y-4)-y-(4(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-4)-(4(y-5))=0

We multiply parentheses

-1y-15y-(4(y-5))+20=0



We calculate terms in parentheses: -(4(y-5)), so:

4(y-5)

We multiply parentheses

4y-20

Back to the equation:

-(4y-20)



We add all the numbers together, and all the variables

-16y-(4y-20)+20=0

We get rid of parentheses

-16y-4y+20+20=0

We add all the numbers together, and all the variables

-20y+40=0

We move all terms containing y to the left, all other terms to the right

-20y=-40

y=-40/-20

y=+2

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