4(k+3)-20=20

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Solution for 4(k+3)-20=20 equation: 



4(k+3)-20=20

We move all terms to the left:

4(k+3)-20-(20)=0

We add all the numbers together, and all the variables

4(k+3)-40=0

We multiply parentheses

4k+12-40=0

We add all the numbers together, and all the variables

4k-28=0

We move all terms containing k to the left, all other terms to the right

4k=28

k=28/4

k=7

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