-5(3y-4)-y=-2(y-2)

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Solution for -5(3y-4)-y=-2(y-2) equation: 



-5(3y-4)-y=-2(y-2)

We move all terms to the left:

-5(3y-4)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-5(3y-4)-(-2(y-2))=0

We multiply parentheses

-1y-15y-(-2(y-2))+20=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We add all the numbers together, and all the variables

-16y-(-2y+4)+20=0

We get rid of parentheses

-16y+2y-4+20=0

We add all the numbers together, and all the variables

-14y+16=0

We move all terms containing y to the left, all other terms to the right

-14y=-16

y=-16/-14

y=1+1/7

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