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0=x2+5x-6.
We move all terms to the left:
0-(x2+5x-6.)=0
We add all the numbers together, and all the variables
-(+x^2+5x-6.)+0=0
We add all the numbers together, and all the variables
-(+x^2+5x-6.)=0
We get rid of parentheses
-x^2-5x+6.=0
We add all the numbers together, and all the variables
-1x^2-5x+6=0
a = -1; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·(-1)·6
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*-1}=\frac{-2}{-2} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*-1}=\frac{12}{-2} =-6 $
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