-5(3y-3)-y=-3(y-5)

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Solution for -5(3y-3)-y=-3(y-5) equation: 



-5(3y-3)-y=-3(y-5)

We move all terms to the left:

-5(3y-3)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-3)-(-3(y-5))=0

We multiply parentheses

-1y-15y-(-3(y-5))+15=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

-16y-(-3y+15)+15=0

We get rid of parentheses

-16y+3y-15+15=0

We add all the numbers together, and all the variables

-13y=0

y=0/-13

y=0

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