2(y-5)-9=-5(-4y+1)-6y

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Solution for 2(y-5)-9=-5(-4y+1)-6y equation: 



2(y-5)-9=-5(-4y+1)-6y

We move all terms to the left:

2(y-5)-9-(-5(-4y+1)-6y)=0

We multiply parentheses

2y-(-5(-4y+1)-6y)-10-9=0



We calculate terms in parentheses: -(-5(-4y+1)-6y), so:

-5(-4y+1)-6y

We add all the numbers together, and all the variables

-6y-5(-4y+1)

We multiply parentheses

-6y+20y-5

We add all the numbers together, and all the variables

14y-5

Back to the equation:

-(14y-5)



We add all the numbers together, and all the variables

2y-(14y-5)-19=0

We get rid of parentheses

2y-14y+5-19=0

We add all the numbers together, and all the variables

-12y-14=0

We move all terms containing y to the left, all other terms to the right

-12y=14

y=14/-12

y=-1+1/6

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