-5(3y-2)=-35

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Solution for -5(3y-2)=-35 equation: 



-5(3y-2)=-35

We move all terms to the left:

-5(3y-2)-(-35)=0

We add all the numbers together, and all the variables

-5(3y-2)+35=0

We multiply parentheses

-15y+10+35=0

We add all the numbers together, and all the variables

-15y+45=0

We move all terms containing y to the left, all other terms to the right

-15y=-45

y=-45/-15

y=+3

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