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4(2x+3)+4(2x+3)+4=16x+28
We move all terms to the left:
4(2x+3)+4(2x+3)+4-(16x+28)=0
We multiply parentheses
8x+8x-(16x+28)+12+12+4=0
We get rid of parentheses
8x+8x-16x-28+12+12+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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