-5(3y-1)+8y=5(y+4)

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Solution for -5(3y-1)+8y=5(y+4) equation: 



-5(3y-1)+8y=5(y+4)

We move all terms to the left:

-5(3y-1)+8y-(5(y+4))=0

We add all the numbers together, and all the variables

8y-5(3y-1)-(5(y+4))=0

We multiply parentheses

8y-15y-(5(y+4))+5=0



We calculate terms in parentheses: -(5(y+4)), so:

5(y+4)

We multiply parentheses

5y+20

Back to the equation:

-(5y+20)



We add all the numbers together, and all the variables

-7y-(5y+20)+5=0

We get rid of parentheses

-7y-5y-20+5=0

We add all the numbers together, and all the variables

-12y-15=0

We move all terms containing y to the left, all other terms to the right

-12y=15

y=15/-12

y=-1+1/4

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