23(3-r)+r-17=89-r+10

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Solution for 23(3-r)+r-17=89-r+10 equation: 



23(3-r)+r-17=89-r+10

We move all terms to the left:

23(3-r)+r-17-(89-r+10)=0

We add all the numbers together, and all the variables

23(-1r+3)+r-(-1r+99)-17=0

We add all the numbers together, and all the variables

r+23(-1r+3)-(-1r+99)-17=0

We multiply parentheses

r-23r-(-1r+99)+69-17=0

We get rid of parentheses

r-23r+1r-99+69-17=0

We add all the numbers together, and all the variables

-21r-47=0

We move all terms containing r to the left, all other terms to the right

-21r=47

r=47/-21

r=-2+5/21

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