-5(3y+-2)=40

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Solution for -5(3y+-2)=40 equation: 



-5(3y+-2)=40

We move all terms to the left:

-5(3y+-2)-(40)=0

We add all the numbers together, and all the variables

-5(3y-2)-40=0

We multiply parentheses

-15y+10-40=0

We add all the numbers together, and all the variables

-15y-30=0

We move all terms containing y to the left, all other terms to the right

-15y=30

y=30/-15

y=-2

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