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12(5+2y)=4y(5-9y)
We move all terms to the left:
12(5+2y)-(4y(5-9y))=0
We add all the numbers together, and all the variables
12(2y+5)-(4y(-9y+5))=0
We multiply parentheses
24y-(4y(-9y+5))+60=0
We calculate terms in parentheses: -(4y(-9y+5)), so:We get rid of parentheses
4y(-9y+5)
We multiply parentheses
-36y^2+20y
Back to the equation:
-(-36y^2+20y)
36y^2-20y+24y+60=0
We add all the numbers together, and all the variables
36y^2+4y+60=0
a = 36; b = 4; c = +60;
Δ = b2-4ac
Δ = 42-4·36·60
Δ = -8624
Delta is less than zero, so there is no solution for the equation
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