-5(3x-9)=2(x-12)-33

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Solution for -5(3x-9)=2(x-12)-33 equation: 



-5(3x-9)=2(x-12)-33

We move all terms to the left:

-5(3x-9)-(2(x-12)-33)=0

We multiply parentheses

-15x-(2(x-12)-33)+45=0



We calculate terms in parentheses: -(2(x-12)-33), so:

2(x-12)-33

We multiply parentheses

2x-24-33

We add all the numbers together, and all the variables

2x-57

Back to the equation:

-(2x-57)



We get rid of parentheses

-15x-2x+57+45=0

We add all the numbers together, and all the variables

-17x+102=0

We move all terms containing x to the left, all other terms to the right

-17x=-102

x=-102/-17

x=+6

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