-5(3-q)+4=2(q-6)+(q+1)

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Solution for -5(3-q)+4=2(q-6)+(q+1) equation: 



-5(3-q)+4=2(q-6)+(q+1)

We move all terms to the left:

-5(3-q)+4-(2(q-6)+(q+1))=0

We add all the numbers together, and all the variables

-5(-1q+3)-(2(q-6)+(q+1))+4=0

We multiply parentheses

5q-(2(q-6)+(q+1))-15+4=0



We calculate terms in parentheses: -(2(q-6)+(q+1)), so:

2(q-6)+(q+1)

We multiply parentheses

2q+(q+1)-12

We get rid of parentheses

2q+q+1-12

We add all the numbers together, and all the variables

3q-11

Back to the equation:

-(3q-11)



We add all the numbers together, and all the variables

5q-(3q-11)-11=0

We get rid of parentheses

5q-3q+11-11=0

We add all the numbers together, and all the variables

2q=0

q=0/2

q=0

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