15x-60x2=0

Solution for 15x-60x2=0 equation:

15x-60x^2=0

a = -60; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-60)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-60}=\frac{-30}{-120}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-60}=\frac{0}{-120}
=0
$