-5(2y+3)+5=40

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Solution for -5(2y+3)+5=40 equation: 



-5(2y+3)+5=40

We move all terms to the left:

-5(2y+3)+5-(40)=0

We add all the numbers together, and all the variables

-5(2y+3)-35=0

We multiply parentheses

-10y-15-35=0

We add all the numbers together, and all the variables

-10y-50=0

We move all terms containing y to the left, all other terms to the right

-10y=50

y=50/-10

y=-5

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