6y+2(y-8)=5(y+1)-4

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Solution for 6y+2(y-8)=5(y+1)-4 equation: 



6y+2(y-8)=5(y+1)-4

We move all terms to the left:

6y+2(y-8)-(5(y+1)-4)=0

We multiply parentheses

6y+2y-(5(y+1)-4)-16=0



We calculate terms in parentheses: -(5(y+1)-4), so:

5(y+1)-4

We multiply parentheses

5y+5-4

We add all the numbers together, and all the variables

5y+1

Back to the equation:

-(5y+1)



We add all the numbers together, and all the variables

8y-(5y+1)-16=0

We get rid of parentheses

8y-5y-1-16=0

We add all the numbers together, and all the variables

3y-17=0

We move all terms containing y to the left, all other terms to the right

3y=17

y=17/3

y=5+2/3

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