-5(2x-5)=2(x-7)-33

Solution for -5(2x-5)=2(x-7)-33 equation:

-5(2x-5)=2(x-7)-33

We move all terms to the left:

-5(2x-5)-(2(x-7)-33)=0

We multiply parentheses

-10x-(2(x-7)-33)+25=0


We calculate terms in parentheses: -(2(x-7)-33), so:

2(x-7)-33

We multiply parentheses

2x-14-33

We add all the numbers together, and all the variables

2x-47

Back to the equation:

-(2x-47)


We get rid of parentheses

-10x-2x+47+25=0

We add all the numbers together, and all the variables

-12x+72=0

We move all terms containing x to the left, all other terms to the right

-12x=-72

x=-72/-12

x=+6