25+3x=6(-x+5)-41

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Solution for 25+3x=6(-x+5)-41 equation: 



25+3x=6(-x+5)-41

We move all terms to the left:

25+3x-(6(-x+5)-41)=0

We add all the numbers together, and all the variables

3x-(6(-1x+5)-41)+25=0



We calculate terms in parentheses: -(6(-1x+5)-41), so:

6(-1x+5)-41

We multiply parentheses

-6x+30-41

We add all the numbers together, and all the variables

-6x-11

Back to the equation:

-(-6x-11)



We get rid of parentheses

3x+6x+11+25=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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