-5(-2u+2)-4u=2(u-7)-6

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Solution for -5(-2u+2)-4u=2(u-7)-6 equation: 



-5(-2u+2)-4u=2(u-7)-6

We move all terms to the left:

-5(-2u+2)-4u-(2(u-7)-6)=0

We add all the numbers together, and all the variables

-4u-5(-2u+2)-(2(u-7)-6)=0

We multiply parentheses

-4u+10u-(2(u-7)-6)-10=0



We calculate terms in parentheses: -(2(u-7)-6), so:

2(u-7)-6

We multiply parentheses

2u-14-6

We add all the numbers together, and all the variables

2u-20

Back to the equation:

-(2u-20)



We add all the numbers together, and all the variables

6u-(2u-20)-10=0

We get rid of parentheses

6u-2u+20-10=0

We add all the numbers together, and all the variables

4u+10=0

We move all terms containing u to the left, all other terms to the right

4u=-10

u=-10/4

u=-2+1/2

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