12+3x+4+3x=2(3x+8)

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Solution for 12+3x+4+3x=2(3x+8) equation: 



12+3x+4+3x=2(3x+8)

We move all terms to the left:

12+3x+4+3x-(2(3x+8))=0

We add all the numbers together, and all the variables

6x-(2(3x+8))+16=0



We calculate terms in parentheses: -(2(3x+8)), so:

2(3x+8)

We multiply parentheses

6x+16

Back to the equation:

-(6x+16)



We get rid of parentheses

6x-6x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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