-4y2+y2=17

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Solution for -4y2+y2=17 equation: 



-4y^2+y2=17

We move all terms to the left:

-4y^2+y2-(17)=0

We add all the numbers together, and all the variables

-3y^2-17=0

a = -3; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·(-3)·(-17)
Δ = -204
Delta is less than zero, so there is no solution for the equation

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