2z+4z/183.25z=z

Solution for 2z+4z/183.25z=z equation:

2z+4z/183.25z=z

We move all terms to the left:

2z+4z/183.25z-(z)=0


Domain of the equation: 183.25z!=0

z!=0/183.25

z!=0

z∈R


We add all the numbers together, and all the variables

z+4z/183.25z=0

We multiply all the terms by the denominator


z*183.25z+4z=0

We add all the numbers together, and all the variables

4z+z*183.25z=0

Wy multiply elements

183z^2+4z=0

a = 183; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·183·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*183}=\frac{-8}{366}
=-4/183
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*183}=\frac{0}{366}
=0
$