-4y(3y-5)=13(3-y)

Solution for -4y(3y-5)=13(3-y) equation:

-4y(3y-5)=13(3-y)

We move all terms to the left:

-4y(3y-5)-(13(3-y))=0

We add all the numbers together, and all the variables

-4y(3y-5)-(13(-1y+3))=0

We multiply parentheses

-12y^2+20y-(13(-1y+3))=0


We calculate terms in parentheses: -(13(-1y+3)), so:

13(-1y+3)

We multiply parentheses

-13y+39

Back to the equation:

-(-13y+39)


We get rid of parentheses

-12y^2+20y+13y-39=0

We add all the numbers together, and all the variables

-12y^2+33y-39=0

a = -12; b = 33; c = -39;
Δ = b2-4ac
Δ = 332-4·(-12)·(-39)
Δ = -783
Delta is less than zero, so there is no solution for the equation