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7v-(2v-16)=5(v+6)
We move all terms to the left:
7v-(2v-16)-(5(v+6))=0
We get rid of parentheses
7v-2v-(5(v+6))+16=0
We calculate terms in parentheses: -(5(v+6)), so:We add all the numbers together, and all the variables
5(v+6)
We multiply parentheses
5v+30
Back to the equation:
-(5v+30)
5v-(5v+30)+16=0
We get rid of parentheses
5v-5v-30+16=0
We add all the numbers together, and all the variables
-14!=0
There is no solution for this equation
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