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-4x(x+8)=32
We move all terms to the left:
-4x(x+8)-(32)=0
We multiply parentheses
-4x^2-32x-32=0
a = -4; b = -32; c = -32;
Δ = b2-4ac
Δ = -322-4·(-4)·(-32)
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-16\sqrt{2}}{2*-4}=\frac{32-16\sqrt{2}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+16\sqrt{2}}{2*-4}=\frac{32+16\sqrt{2}}{-8} $
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