4(y-3)=-2y+36

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Solution for 4(y-3)=-2y+36 equation: 



4(y-3)=-2y+36

We move all terms to the left:

4(y-3)-(-2y+36)=0

We multiply parentheses

4y-(-2y+36)-12=0

We get rid of parentheses

4y+2y-36-12=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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