-4x(3x-20)=1-12x

Solution for -4x(3x-20)=1-12x equation:

-4x(3x-20)=1-12x

We move all terms to the left:

-4x(3x-20)-(1-12x)=0

We add all the numbers together, and all the variables

-4x(3x-20)-(-12x+1)=0

We multiply parentheses

-12x^2+80x-(-12x+1)=0

We get rid of parentheses

-12x^2+80x+12x-1=0

We add all the numbers together, and all the variables

-12x^2+92x-1=0

a = -12; b = 92; c = -1;
Δ = b2-4ac
Δ = 922-4·(-12)·(-1)
Δ = 8416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8416}=\sqrt{16*526}=\sqrt{16}*\sqrt{526}=4\sqrt{526}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-4\sqrt{526}}{2*-12}=\frac{-92-4\sqrt{526}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+4\sqrt{526}}{2*-12}=\frac{-92+4\sqrt{526}}{-24}
$