5=3(f-5)+-4

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Solution for 5=3(f-5)+-4 equation: 



5=3(f-5)+-4

We move all terms to the left:

5-(3(f-5)+-4)=0

We use the square of the difference formula

-(3(f-5)-4)+5=0



We calculate terms in parentheses: -(3(f-5)-4), so:

3(f-5)-4

We multiply parentheses

3f-15-4

We add all the numbers together, and all the variables

3f-19

Back to the equation:

-(3f-19)



We get rid of parentheses

-3f+19+5=0

We add all the numbers together, and all the variables

-3f+24=0

We move all terms containing f to the left, all other terms to the right

-3f=-24

f=-24/-3

f=+8

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