-4v-2=2v-2+(v+100)/4

Solution for -4v-2=2v-2+(v+100)/4 equation:

-4v-2=2v-2+(v+100)/4

We move all terms to the left:

-4v-2-(2v-2+(v+100)/4)=0

We multiply all the terms by the denominator


-4v*4)-(2v+(v+100)-2-2*4)=0

We add all the numbers together, and all the variables

-4v*4)-(2v+(v+100)=0

Wy multiply elements

-16v^2+(v+100)=0

We get rid of parentheses

-16v^2+v+100=0

a = -16; b = 1; c = +100;
Δ = b2-4ac
Δ = 12-4·(-16)·100
Δ = 6401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{6401}}{2*-16}=\frac{-1-\sqrt{6401}}{-32}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{6401}}{2*-16}=\frac{-1+\sqrt{6401}}{-32}
$