-4v+40=8(v-2)

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Solution for -4v+40=8(v-2) equation: 



-4v+40=8(v-2)

We move all terms to the left:

-4v+40-(8(v-2))=0



We calculate terms in parentheses: -(8(v-2)), so:

8(v-2)

We multiply parentheses

8v-16

Back to the equation:

-(8v-16)



We get rid of parentheses

-4v-8v+16+40=0

We add all the numbers together, and all the variables

-12v+56=0

We move all terms containing v to the left, all other terms to the right

-12v=-56

v=-56/-12

v=4+2/3

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