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16x+10((98-16x)/10)=98
We move all terms to the left:
16x+10((98-16x)/10)-(98)=0
We add all the numbers together, and all the variables
16x+10((-16x+98)/10)-98=0
We multiply all the terms by the denominator
16x*10)+10((-16x+98)-98*10)=0
We add all the numbers together, and all the variables
16x*10)+10((-16x+98)=0
Wy multiply elements
160x^2=0
a = 160; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·160·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{320}=0$
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