-4u(4u-4)+6u=5(u+5)

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Solution for -4u(4u-4)+6u=5(u+5) equation: 



-4u(4u-4)+6u=5(u+5)

We move all terms to the left:

-4u(4u-4)+6u-(5(u+5))=0

We add all the numbers together, and all the variables

6u-4u(4u-4)-(5(u+5))=0

We multiply parentheses

-16u^2+6u+16u-(5(u+5))=0



We calculate terms in parentheses: -(5(u+5)), so:

5(u+5)

We multiply parentheses

5u+25

Back to the equation:

-(5u+25)



We add all the numbers together, and all the variables

-16u^2+22u-(5u+25)=0

We get rid of parentheses

-16u^2+22u-5u-25=0

We add all the numbers together, and all the variables

-16u^2+17u-25=0

a = -16; b = 17; c = -25;
Δ = b2-4ac
Δ = 172-4·(-16)·(-25)
Δ = -1311
Delta is less than zero, so there is no solution for the equation

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