X+x+2=3(x+1)+12

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Solution for X+x+2=3(x+1)+12 equation: 



X+X+2=3(X+1)+12

We move all terms to the left:

X+X+2-(3(X+1)+12)=0

We add all the numbers together, and all the variables

2X-(3(X+1)+12)+2=0



We calculate terms in parentheses: -(3(X+1)+12), so:

3(X+1)+12

We multiply parentheses

3X+3+12

We add all the numbers together, and all the variables

3X+15

Back to the equation:

-(3X+15)



We get rid of parentheses

2X-3X-15+2=0

We add all the numbers together, and all the variables

-1X-13=0

We move all terms containing X to the left, all other terms to the right

-X=13

X=13/-1

X=-13

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