-4r+2(r+1)=-r+7(1+6r)

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Solution for -4r+2(r+1)=-r+7(1+6r) equation: 



-4r+2(r+1)=-r+7(1+6r)

We move all terms to the left:

-4r+2(r+1)-(-r+7(1+6r))=0

We add all the numbers together, and all the variables

-4r+2(r+1)-(-r+7(6r+1))=0

We multiply parentheses

-4r+2r-(-r+7(6r+1))+2=0



We calculate terms in parentheses: -(-r+7(6r+1)), so:

-r+7(6r+1)

We add all the numbers together, and all the variables

-1r+7(6r+1)

We multiply parentheses

-1r+42r+7

We add all the numbers together, and all the variables

41r+7

Back to the equation:

-(41r+7)



We add all the numbers together, and all the variables

-2r-(41r+7)+2=0

We get rid of parentheses

-2r-41r-7+2=0

We add all the numbers together, and all the variables

-43r-5=0

We move all terms containing r to the left, all other terms to the right

-43r=5

r=5/-43

r=-5/43

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