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(1)/(4)k=3(-(1)/(4)k+3)
We move all terms to the left:
(1)/(4)k-(3(-(1)/(4)k+3))=0
Domain of the equation: 4k!=0
k!=0/4
k!=0
k∈R
Domain of the equation: 4k+3))!=0We calculate fractions
k∈R
4k/16k^2+(-(3(-1*4k)/16k^2=0
We multiply all the terms by the denominator
4k+(-(3(-1*4k)=0
We calculate terms in parentheses: +(-(3(-1*4k), so:
-(3(-1*4k
We calculate terms in parentheses: +(-(3(-1*4k), so:
-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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-(3(-1*4k
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| -3(x+9)+8=-18 | | 5+1=2(4x-3) | | z+35=87 | | 6.5-0.6x+3.1-0.7x=0.5 | | 3h=7(2)/(7)-(3)/(7)h)-10 | | X=0.4x+0.3 | | 3p+2=2(p+3) | | 1990=0.13x+70.0 | | 2x÷3-x÷2=30 | | m-4(-5-2)=(6-3)-(5-8) | | 9x-7x=4x-8 | | 14+6x=2x | | 7x-1=4+4= | | 2x=5x-96 | | 18*x=192 | | -2(-x+9)-4x=3(5x-8) | | X^2+25x+74=0 | | 6(x+3)-4x=2 | | 4n+3n+2n=72 | | 5x+27=2x+57 | | 3a+5=12a-4 | | -8+m/3=-3 | | -5=-7+x/8 | | -61=-1-4k | | 2x+-5=29 | | x^{3}+5x+2=0 | | x+12/3*4x=0.5x | | 2x2+5x+3=0. | | 3t+3=42 | | 5x^2+0=0 | | 5x^2+0=5x^2 | | (3x)(0x)=0 |