-4m-2m=5(2m-4)-21-2+6m)

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Solution for -4m-2m=5(2m-4)-21-2+6m) equation: 



-4m-2m=5(2m-4)-21-2+6m)

We move all terms to the left:

-4m-2m-(5(2m-4)-21-2+6m))=0

We add all the numbers together, and all the variables

-6m-(5(2m-4)-21-2+6m))=0



We calculate terms in parentheses: -(5(2m-4)-21-2+6m)), so:

5(2m-4)-21-2+6m)

determiningTheFunctionDomain
5(2m-4)+6m)-21-2

We multiply parentheses

10m+6m)-21-2-20

Back to the equation:

-(10m+6m)-21-2-20)



We add all the numbers together, and all the variables

-6m-(+16m)-21-2-20)=0

We add all the numbers together, and all the variables

-6m-(+16m)=0

We get rid of parentheses

-6m-16m=0

We add all the numbers together, and all the variables

-22m=0

m=0/-22

m=0

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