6+(3z-1)/8=2z+11

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Solution for 6+(3z-1)/8=2z+11 equation: 



6+(3z-1)/8=2z+11

We move all terms to the left:

6+(3z-1)/8-(2z+11)=0

We get rid of parentheses

(3z-1)/8-2z-11+6=0

We multiply all the terms by the denominator


(3z-1)-2z*8-11*8+6*8=0

We add all the numbers together, and all the variables

(3z-1)-2z*8-40=0

Wy multiply elements

(3z-1)-16z-40=0

We get rid of parentheses

3z-16z-1-40=0

We add all the numbers together, and all the variables

-13z-41=0

We move all terms containing z to the left, all other terms to the right

-13z=41

z=41/-13

z=-3+2/13

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