-4m+13-5(m-3)=3m-(2m-5)-7m+8

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Solution for -4m+13-5(m-3)=3m-(2m-5)-7m+8 equation: 



-4m+13-5(m-3)=3m-(2m-5)-7m+8

We move all terms to the left:

-4m+13-5(m-3)-(3m-(2m-5)-7m+8)=0

We multiply parentheses

-4m-5m-(3m-(2m-5)-7m+8)+15+13=0



We calculate terms in parentheses: -(3m-(2m-5)-7m+8), so:

3m-(2m-5)-7m+8

We add all the numbers together, and all the variables

-4m-(2m-5)+8

We get rid of parentheses

-4m-2m+5+8

We add all the numbers together, and all the variables

-6m+13

Back to the equation:

-(-6m+13)



We add all the numbers together, and all the variables

-9m-(-6m+13)+28=0

We get rid of parentheses

-9m+6m-13+28=0

We add all the numbers together, and all the variables

-3m+15=0

We move all terms containing m to the left, all other terms to the right

-3m=-15

m=-15/-3

m=+5

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