-4h+2(1-h)=3h-4(2+h)

Solution for -4h+2(1-h)=3h-4(2+h) equation:

-4h+2(1-h)=3h-4(2+h)

We move all terms to the left:

-4h+2(1-h)-(3h-4(2+h))=0

We add all the numbers together, and all the variables

-4h+2(-1h+1)-(3h-4(h+2))=0

We multiply parentheses

-4h-2h-(3h-4(h+2))+2=0


We calculate terms in parentheses: -(3h-4(h+2)), so:

3h-4(h+2)

We multiply parentheses

3h-4h-8

We add all the numbers together, and all the variables

-1h-8

Back to the equation:

-(-1h-8)


We add all the numbers together, and all the variables

-6h-(-1h-8)+2=0

We get rid of parentheses

-6h+1h+8+2=0

We add all the numbers together, and all the variables

-5h+10=0

We move all terms containing h to the left, all other terms to the right

-5h=-10

h=-10/-5

h=+2