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2x(2x+6)=10x+6
We move all terms to the left:
2x(2x+6)-(10x+6)=0
We multiply parentheses
4x^2+12x-(10x+6)=0
We get rid of parentheses
4x^2+12x-10x-6=0
We add all the numbers together, and all the variables
4x^2+2x-6=0
a = 4; b = 2; c = -6;
Δ = b2-4ac
Δ = 22-4·4·(-6)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*4}=\frac{-12}{8} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*4}=\frac{8}{8} =1 $
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