-4c(-c-8)=4c-8

Solution for -4c(-c-8)=4c-8 equation:

-4c(-c-8)=4c-8

We move all terms to the left:

-4c(-c-8)-(4c-8)=0

We add all the numbers together, and all the variables

-4c(-1c-8)-(4c-8)=0

We multiply parentheses

4c^2+32c-(4c-8)=0

We get rid of parentheses

4c^2+32c-4c+8=0

We add all the numbers together, and all the variables

4c^2+28c+8=0

a = 4; b = 28; c = +8;
Δ = b2-4ac
Δ = 282-4·4·8
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{41}}{2*4}=\frac{-28-4\sqrt{41}}{8}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{41}}{2*4}=\frac{-28+4\sqrt{41}}{8}
$