12h-(3-h)=7(5h-1)-18h

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Solution for 12h-(3-h)=7(5h-1)-18h equation: 



12h-(3-h)=7(5h-1)-18h

We move all terms to the left:

12h-(3-h)-(7(5h-1)-18h)=0

We add all the numbers together, and all the variables

12h-(-1h+3)-(7(5h-1)-18h)=0

We get rid of parentheses

12h+1h-(7(5h-1)-18h)-3=0



We calculate terms in parentheses: -(7(5h-1)-18h), so:

7(5h-1)-18h

We add all the numbers together, and all the variables

-18h+7(5h-1)

We multiply parentheses

-18h+35h-7

We add all the numbers together, and all the variables

17h-7

Back to the equation:

-(17h-7)



We add all the numbers together, and all the variables

13h-(17h-7)-3=0

We get rid of parentheses

13h-17h+7-3=0

We add all the numbers together, and all the variables

-4h+4=0

We move all terms containing h to the left, all other terms to the right

-4h=-4

h=-4/-4

h=1

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