-49=3(1+3r)+4r

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Solution for -49=3(1+3r)+4r equation: 



-49=3(1+3r)+4r

We move all terms to the left:

-49-(3(1+3r)+4r)=0

We add all the numbers together, and all the variables

-(3(3r+1)+4r)-49=0



We calculate terms in parentheses: -(3(3r+1)+4r), so:

3(3r+1)+4r

We add all the numbers together, and all the variables

4r+3(3r+1)

We multiply parentheses

4r+9r+3

We add all the numbers together, and all the variables

13r+3

Back to the equation:

-(13r+3)



We get rid of parentheses

-13r-3-49=0

We add all the numbers together, and all the variables

-13r-52=0

We move all terms containing r to the left, all other terms to the right

-13r=52

r=52/-13

r=-4

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