-42+20z=5(4z-10)+8

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Solution for -42+20z=5(4z-10)+8 equation: 



-42+20z=5(4z-10)+8

We move all terms to the left:

-42+20z-(5(4z-10)+8)=0



We calculate terms in parentheses: -(5(4z-10)+8), so:

5(4z-10)+8

We multiply parentheses

20z-50+8

We add all the numbers together, and all the variables

20z-42

Back to the equation:

-(20z-42)



We get rid of parentheses

20z-20z+42-42=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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