-40=5(1-6r)+3(r-4)

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Solution for -40=5(1-6r)+3(r-4) equation: 



-40=5(1-6r)+3(r-4)

We move all terms to the left:

-40-(5(1-6r)+3(r-4))=0

We add all the numbers together, and all the variables

-(5(-6r+1)+3(r-4))-40=0



We calculate terms in parentheses: -(5(-6r+1)+3(r-4)), so:

5(-6r+1)+3(r-4)

We multiply parentheses

-30r+3r+5-12

We add all the numbers together, and all the variables

-27r-7

Back to the equation:

-(-27r-7)



We get rid of parentheses

27r+7-40=0

We add all the numbers together, and all the variables

27r-33=0

We move all terms containing r to the left, all other terms to the right

27r=33

r=33/27

r=1+2/9

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