-4-c=-3(2c-6)+3c

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Solution for -4-c=-3(2c-6)+3c equation: 



-4-c=-3(2c-6)+3c

We move all terms to the left:

-4-c-(-3(2c-6)+3c)=0

We add all the numbers together, and all the variables

-1c-(-3(2c-6)+3c)-4=0



We calculate terms in parentheses: -(-3(2c-6)+3c), so:

-3(2c-6)+3c

We add all the numbers together, and all the variables

3c-3(2c-6)

We multiply parentheses

3c-6c+18

We add all the numbers together, and all the variables

-3c+18

Back to the equation:

-(-3c+18)



We get rid of parentheses

-1c+3c-18-4=0

We add all the numbers together, and all the variables

2c-22=0

We move all terms containing c to the left, all other terms to the right

2c=22

c=22/2

c=11

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