-4-4(3+2n)=12(n+7)

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Solution for -4-4(3+2n)=12(n+7) equation: 



-4-4(3+2n)=12(n+7)

We move all terms to the left:

-4-4(3+2n)-(12(n+7))=0

We add all the numbers together, and all the variables

-4(2n+3)-(12(n+7))-4=0

We multiply parentheses

-8n-(12(n+7))-12-4=0



We calculate terms in parentheses: -(12(n+7)), so:

12(n+7)

We multiply parentheses

12n+84

Back to the equation:

-(12n+84)



We add all the numbers together, and all the variables

-8n-(12n+84)-16=0

We get rid of parentheses

-8n-12n-84-16=0

We add all the numbers together, and all the variables

-20n-100=0

We move all terms containing n to the left, all other terms to the right

-20n=100

n=100/-20

n=-5

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