-25=1/5(10x-2)+3x

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Solution for -25=1/5(10x-2)+3x equation: 



-25=1/5(10x-2)+3x

We move all terms to the left:

-25-(1/5(10x-2)+3x)=0



Domain of the equation: 5(10x-2)+3x)!=0

x∈R



We multiply all the terms by the denominator


-(1-25*5(10x-2)+3x)=0



We calculate terms in parentheses: -(1-25*5(10x-2)+3x), so:

1-25*5(10x-2)+3x

determiningTheFunctionDomain
-25*5(10x-2)+3x+1

We add all the numbers together, and all the variables

3x-25*5(10x-2)+1

Wy multiply elements

3x-125x(1+1

Back to the equation:

-(3x-125x(1+1)



We add all the numbers together, and all the variables

-(3x-125x2=0

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