-4-(2+3x)=3(2x-1)+5

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Solution for -4-(2+3x)=3(2x-1)+5 equation: 



-4-(2+3x)=3(2x-1)+5

We move all terms to the left:

-4-(2+3x)-(3(2x-1)+5)=0

We add all the numbers together, and all the variables

-(3x+2)-(3(2x-1)+5)-4=0

We get rid of parentheses

-3x-(3(2x-1)+5)-2-4=0



We calculate terms in parentheses: -(3(2x-1)+5), so:

3(2x-1)+5

We multiply parentheses

6x-3+5

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

-3x-(6x+2)-6=0

We get rid of parentheses

-3x-6x-2-6=0

We add all the numbers together, and all the variables

-9x-8=0

We move all terms containing x to the left, all other terms to the right

-9x=8

x=8/-9

x=-8/9

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